What are the oxidation states of both the chl | vedclass

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Question

(D) Bleaching powder is represented as $Ca(OCl)Cl$. It consists of a calcium ion $(Ca^{2+})$,a hypochlorite ion $(OCl^-)$,and a chloride ion $(Cl^-)$.

Vedclass · Accepted Answer

$+1, -1$

Vedclass · Answer

(D) Bleaching powder is represented as $Ca(OCl)Cl$. It consists of a calcium ion $(Ca^{2+})$,a hypochlorite ion $(OCl^-)$,and a chloride ion $(Cl^-)$. In the hypochlorite ion $(OCl^-)$,the oxygen atom has an oxidation state of $-2$. Let the oxidation state of chlorine be $x$. $x + (-2) = -1 \implies x = +1$. In the chloride ion $(Cl^-)$,the oxidation state of chlorine is $-1$. Therefore,the oxidation states of the two chlorine atoms are $+1$ and $-1$.

List $I$ (Compound)	List $II$ (Oxidation state of $N$)
$(A)$ $NO_2$	$(1)$ $+5$
$(B)$ $HNO$	$(2)$ $-3$
$(C)$ $NH_3$	$(3)$ $+4$
$(D)$ $N_2O_5$	$(4)$ $+1$

What are the oxidation states of both the chlorine atoms in bleaching powder $(CaOCl_2)$?

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Match List $I$ with List $II$ and select the correct answer using the codes given below the lists:
List $I$ (Compound) List $II$ (Oxidation state of $N$)
$(A)$ $NO_2$ $(1)$ $+5$
$(B)$ $HNO$ $(2)$ $-3$
$(C)$ $NH_3$ $(3)$ $+4$
$(D)$ $N_2O_5$ $(4)$ $+1$

Codes: $A \quad B \quad C \quad D$

What is the oxidation number of $Cl$ in $CaOCl_2$?

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